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水泥廠(chǎng)廢氣處理系統物料平衡及熱平衡計算

2022-09-13 09:30:34
動(dòng)態(tài)詳情

水泥廠(chǎng)廢氣處理系統物料平衡及熱平衡計算

.計算條件

 

1,物料

 

①易磨性:m0

 

②粉磨前綜合水份:×m1=2.5%;

 

③粉磨后綜合水份:×m2=0.5%;

 

④粉磨前物料溫度:Tm1=150C;

 

⑤粉磨后物料溫度:Tm2=850C;

 

2,窯氣

 

①體積:VK=1.5131Nm3/Kg-cl×5000×1.1×1000/24=346750Nm3/h;

 

②燒成系統設計能力:5000t/d,放大系數:1.1;

 

③溫度:TK=3300C;

 

④濕度:WK=70%;

 

⑤含塵量:AK=55g/Nm3;

 

⑥入煤磨窯氣量:Vk2=52650Nm3/h(溫度:Tg1=3100C);

 

3,磨機

 

①型號:Ato×50;

 

②原料磨系統設計能力:G0=400t/h;

 

③要求入磨風(fēng)量:Vg1=478725Nm3/h(溫度:Tg1=200~3500C);

 

4,環(huán)境

 

①溫度:Ta=150C;

 

②濕度:Wa=50%;

 

,物料平衡

 

①喂料量:Gm1=G0×100/(100-×m1)=400×100/(100-2.5)=410.2t/h;

 

②出磨料量:Gm2=G0×100/(100-×m2)+Vk×Ak/106

 

=400×100/(100-0.5)+346750×55/106=421.1t/h;

 

③蒸發(fā)水量:GH2O=G0×100/(100-×m2)×(×m1-×m2)/(100-×m1)

 

=400×100/(100-0.5)×(2.5-0.5)/(100-2.5)=8.25t/h;

 

④入磨氣體量:Vg1=478725Nm3/h;

 

⑤出磨氣體量:Vg2=Vg1+VH2O+Vs+Vf=1.05(Vg1+VH2O+Vs)

 

=1.05(478725+1.25×8.25×1000+3000)

 

=516639Nm3/h;

 

,熱平衡

 

①入磨處需熱量:Qg1=Qm+QH2O+Qg2+Qd-Qgr

 

物料溫升吸熱:Qm=Gm1×Cm×(Tm2-Tm1)=410.2×0.932×(85-15)×1000

 

=26761448kj/h

 

蒸發(fā)水份吸熱:QH2O=1000GH2O[(100-Tm1)×4.187+2257-(100-Tg2)×1.868]

 

=1000×8.25×[(100-15)×4.187+2257-(100-95)×1.868]

 

=21171109kj/h

 

出磨氣體熱焓:Qg2=Vg2×Cg2×Tg2=516639×1.34×95=65768145kj/h

 

粉磨過(guò)程產(chǎn)生熱量:Qgr=3600×0.9×(G0×P0+Ps)=3600×0.9×(400×8.72+160)

 

=11819520kj/h

 

表面散熱:Qd按其余各項5%計;

 

:Qg1=1.05×(26761448+21171109+65768145-11819520)=1.06975×108kj/h

 

②窯氣熱焓:QK=Vk(Ck+Ak×Cm/1000)×Tk=346750(1.45+55×0.932/1000)×310

 

=1.61374×108kj/h

 

③入煤磨窯氣熱焓:QK2=Vk2(Ck+Ak×Cm/1000)×Tk=52650(1.45+55×0.932/1000)×310

 

=0.24482×108kj/h

 

,討論:

 

情形1,窯開(kāi).原料磨開(kāi).煤磨開(kāi)Qg1+QK2=1.06975×108+0.24482×108=1.31457×108kj/h<QK=1.61374×108kj/h

 

Vg1+Vk2=478725+52650=531375Nm3/h>Vk=346750Nm3/h

 

:窯氣的熱焓大于原料磨及煤磨烘干原燃料所需熱焓,而窯氣量卻小于入磨所需風(fēng)量;故原料磨進(jìn)風(fēng)口須摻冷風(fēng)或摻循環(huán)風(fēng),為了讓盡可能多的窯氣入原料磨,其進(jìn)風(fēng)口只摻冷風(fēng)而不摻循環(huán)風(fēng),以減少進(jìn)增濕塔的廢氣處理量,從而減小電收塵器及原料磨系統風(fēng)機的規格.

 

設摻冷風(fēng)Va后,入原料磨的窯氣量為Vk1;

 

QK1+Qa=1.06975×108kj/h

 

Ck×Vk1×Tk+Ca×Va×Ta=1.06975×108

 

Vk1+Va=478725

 

:1.48×Vk1×310+1.295×(478725-Vk1)×15=1.06975×108

 

:Vk1=2.22306×105Nm3/h

 

Va=(4.78725-2.22306)×105=2.56419×105Nm3/h

 

這種情況下,進(jìn)增濕塔的窯氣處理量為:

 

Vk3=346750-(2.22306×105+52650)=71794Nm3/h

 

進(jìn)增濕塔的窯氣從3100C降到1500C需噴水量GH2O(T)

 

1000×GH2O(T)×[(100-15)×4.187+2257]=71794×1.48×(310-150)

 

GH2O(T)=17000819/2612895=6.51t/h

 

蒸氣量:VH2O(T)=1.25×1000×6.51=8133Nm3/h

 

出增濕塔的廢氣量為:

 

VT=1.05(Vk3+VH2O(T))=1.05×(71794+8133)=83923Nm3/h

 

進(jìn)電收塵器的廢氣量為:

 

VEP=Vg2+VT=516639+83923=600562Nm3/h

 

進(jìn)電收塵器的廢氣溫度為:

 

TEP=(516639×95+83923×150)/625814=98.50C

 

進(jìn)電收塵器負壓為:-10000Pa

 

則進(jìn)電收塵器的廢氣量為:

 

VEP=600562×(273+98.5)/273×101325/(101325-10000)

 

=600562×1.36×1.109=905791m3/h

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